secx/sinx-sinx/cosx=cotx

My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
1. 2 answers
2. asked by Jon
3. 941 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 994 views
how do i simplify (secx - cosx) / sinx?i tried splitting the numerator up so that i had (secx / sinx) - (cosx / sinx) and then i
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2. asked by v
3. 5,794 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,462 views
i have a few questionscosx + cosx =2secx ----- ----- 1+sinx 1-sinx cos(x-B)-cos(x-B) = 2sinxsinB csc2x= 1 secx cscx --- 2 cotx=
1. 4 answers
2. asked by jessika
3. 1,275 views
Hi, I need a bit of help with verifying identities. The problems are as follows:sinx+cosx/cotx+1=sinx sin2x/sin -
1. 2 answers
2. asked by Retrograde
3. 643 views
I'm working this problem:∫ [1-tan^2 (x)] / [sec^2 (x)] dx ∫(1/secx)-[(sin^2x/cos^2x)/(1/cosx) ∫cosx-sinx(sinx/cosx)
1. 1 answer
2. asked by Janice
3. 711 views
Write in terms of cos and sin function.cotx*secx Show work. I know cotx = cosx/sinx and secx = 1/cosx, would that just be the
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2. asked by Need this asap please
3. 633 views
Verify the identity .(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
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2. asked by Rose
3. 741 views
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equationProblem 1.
1. 2 answers
2. asked by Alycia
3. 728 views