Asked by Retrograde
                Hi, I need a bit of help with verifying identities. The problems are as follows:
sinx+cosx/cotx+1=sinx
sin2x/sin - cos2x/cosx=secx
1-tan^2θ/1+tan^2θ=cos2θ
            
        sinx+cosx/cotx+1=sinx
sin2x/sin - cos2x/cosx=secx
1-tan^2θ/1+tan^2θ=cos2θ
Answers
                    Answered by
            Damon
            
    sin x + cos x / cos x/sin x +1 = ?
sin x + sin x + 1 = sin x no way
maybe you mean
(sinx+cosx)/ (cotx+1)
(sin x + cos x) / (cos x/sin x + sin x/sin x)
sin x ( sin x + cos x) / (cos x + sin x)
= sin x yes
Parentheses are VITAL !!!!!
                    Answered by
            oobleck
            
    sin2x/sin - cos2x/cosx
= 2sinx cosx/sinx - (1-2sin^2x)/cosx
= 2cosx - secx + 2sin^2x/cosx
= (2cos^2x+2sin^2x)/cosx - secx
see if you can finish it from here
1-tan^2θ/1+tan^2θ
= (1-(sec^2θ - 1)/sec^2θ
= (2 - sec^2θ)/sec^2θ
see if you can finish it off from here.
    
= 2sinx cosx/sinx - (1-2sin^2x)/cosx
= 2cosx - secx + 2sin^2x/cosx
= (2cos^2x+2sin^2x)/cosx - secx
see if you can finish it from here
1-tan^2θ/1+tan^2θ
= (1-(sec^2θ - 1)/sec^2θ
= (2 - sec^2θ)/sec^2θ
see if you can finish it off from here.
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