find indefinite integral [(sinx)^3]*[(cosx)^3] dx

find indefinite integral [(sinx)^3]*[(cosx)^3] dxi got 1/192 * ((cos(6x)-9cos(2x)) + C but this isnt right. explain plz? thnx
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2. asked by Mikey
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find indefinite integral [(sinx)^3]*[(cosx)^3] dxi got 1/192 * ((cos(6x)-9cos(2x)) + C but this isnt right. explain plz? thnx
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2. asked by Mikey
3. 435 views
Use the symmetry of the graphs of the sine and cosine functions as an aid in evaluating each definite integral.(a) Integral of
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2. asked by John
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1. Find the indefinite integral.Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the
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2. asked by Zooey
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Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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2. asked by Anonymous
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Hello Everyone,I need help with Calc II. 1. Integral from 0 to 1 of (sin(3*pi*t))dt For this one, I got -1/3pi cos (9 pi^2) +
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2. asked by Shelley
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I ran across this one the other day. See what you can make of it.Find the integral of e<sup><sup>cosx</sup></sup>sinx -
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2. asked by oobleck
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If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
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2. asked by Anonymous
3. 716 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
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Find the derivative of the function.y = integral from cosx to sinx (ln(8+3v)) dv lower limit = cosx upper limit = sinx y'(x) =
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2. asked by Tim
3. 1,594 views