Asked by Tim
Find the derivative of the function.
y = integral from cosx to sinx
(ln(8+3v)) dv
lower limit = cosx
upper limit = sinx
y'(x) = ????
y = integral from cosx to sinx
(ln(8+3v)) dv
lower limit = cosx
upper limit = sinx
y'(x) = ????
Answers
Answered by
Steve
Just use Lebniz's Rule:
d/dx ∫[a(x),b(x)] f(t) dt =
f(b(x))b' - f(a(x))a'
d/dx ∫[cosx,sinx] ln(8+3v) dv
= ln(8+3sinx)(cosx) - ln(8+3cosx)(-sinx)
d/dx ∫[a(x),b(x)] f(t) dt =
f(b(x))b' - f(a(x))a'
d/dx ∫[cosx,sinx] ln(8+3v) dv
= ln(8+3sinx)(cosx) - ln(8+3cosx)(-sinx)
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