Asked by Chris

find the derivative of the function


integral from cosx to sinx (ln(8+3v)dv)

y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2

Is this the right answer?????

Answered by Damon
I gave you my answer which is quite different.
Answered by Steve
Hmm. I thought that, using Leibniz' Rule,

F'(x) = ln(8+3sinx)*cosx - ln(8+3cosx)(-sinx)

Did I miss something there?
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