Asked by mike
find the derivative of the function (6x+1)/(19x+1)^1/2
PLEASE EXPLAIN IM LOST
PLEASE EXPLAIN IM LOST
Answers
Answered by
Sarah
You use the quotient rule of :[u'v -uv']/v^2
so:
u=(6x+1) v=(19x+1)^1/2
u'=6 v'= [1/2(19x+1)^-1/2] (19)
y' = 6[(19x+1)^1/2] - (6x+1)[1/2(19x+1)^-1/2] (19)
you can simplify it by taking a common factor. In this case its easier to take (19x+1)^-1/2--- Always take the lowest common factor.
y'=[[19x+1]^-1/2] 6(19x+1) -(6x+1)(1/2)(19)
y'=[[19x+1]^-1/2] 114x+6-57x+9.5
Final answer:
y'=[[19x+1]^-1/2] 57x + 15.5
so:
u=(6x+1) v=(19x+1)^1/2
u'=6 v'= [1/2(19x+1)^-1/2] (19)
y' = 6[(19x+1)^1/2] - (6x+1)[1/2(19x+1)^-1/2] (19)
you can simplify it by taking a common factor. In this case its easier to take (19x+1)^-1/2--- Always take the lowest common factor.
y'=[[19x+1]^-1/2] 6(19x+1) -(6x+1)(1/2)(19)
y'=[[19x+1]^-1/2] 114x+6-57x+9.5
Final answer:
y'=[[19x+1]^-1/2] 57x + 15.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.