consider the funciton f(x)=4.5x-cosx+1 on

  1. Marna wants to find the values of x for which the funciton below will have a value of 10. f(x) = x^2 + x - 20. Which of the
    1. answers icon 1 answer
    2. Jane asked by Jane
    3. views icon 521 views
  2. consider the funciton f(x)=4.5x-cosx+1 on the interval 0≤ x ≤1. the intermediate value theorem guarantees that there is a
    1. answers icon 2 answers
    2. Emily asked by Emily
    3. views icon 467 views
  3. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,142 views
  4. hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
    1. answers icon 0 answers
    2. elle asked by elle
    3. views icon 780 views
  5. I have a question relating to limits that I solvedlim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
    1. answers icon 1 answer
    2. Alex asked by Alex
    3. views icon 734 views
  6. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
    2. Dave asked by Dave
    3. views icon 1,500 views
  7. sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 966 views
  8. Solve this equation fo rx in the interval 0<=x<=3603sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
    1. answers icon 0 answers
    2. Edward asked by Edward
    3. views icon 1,033 views
  9. I can't seem to prove these trig identities and would really appreciate help:1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
    1. answers icon 1 answer
    2. Heather asked by Heather
    3. views icon 1,333 views
  10. i am trying to solve for A and B....this question comes from a Differential equations...but this step goes back to basics...Asin
    1. answers icon 2 answers
    2. mary asked by mary
    3. views icon 655 views