Asked by mary
i am trying to solve for A and B....this question comes from a Differential equations...but this step goes back to basics...
Asinx-Bcosx+6Acosx+6Bsinx=3-cosx
when you group all the sinx and cosx
you get
(A+6B)sinx+(6A-B)cosx=3-cosx
you get
(A+6B)=0 and (6A-B)=-1<<<<<<<<<
i am having a hard time understanding the second part where i have the <<<< next to it...i mean shouldnt it be =-3 i really don't get that...i got this answer from the back of the book but i am trying to understand it...please help if possible...
Asinx-Bcosx+6Acosx+6Bsinx=3-cosx
when you group all the sinx and cosx
you get
(A+6B)sinx+(6A-B)cosx=3-cosx
you get
(A+6B)=0 and (6A-B)=-1<<<<<<<<<
i am having a hard time understanding the second part where i have the <<<< next to it...i mean shouldnt it be =-3 i really don't get that...i got this answer from the back of the book but i am trying to understand it...please help if possible...
Answers
Answered by
mary
plz someone help me...if anyone knowssssssss
Answered by
bobpursley
The point of what you are doing is finding a particular solution. Ignore the -3, get the like coefficents as in the text, solve for A,B. Then you go back and try the solution you found to see if it works in the differential equation. If it does, you are ok with a particular solution. If it does not, often that checking will suggest a modification to your solution. This method is not exact, it sometimes takes iterations.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.