Using the quotient rule, find

  1. f(x)=5+(6/x)+(7/x^2), find f'(x).I haven't done fractions without using the quotient rule im not so sure this would work with
    1. answers icon 1 answer
    2. John asked by John
    3. views icon 468 views
  2. Find the derivative of [(2+x)/(x-3)]^(2/5)I tried the power of a function rule, quotient rule, the chain rule but keep getting
    1. answers icon 2 answers
    2. Sam asked by Sam
    3. views icon 699 views
  3. Match the proper exponent rule (law) below* 5 points (a/b)^m = a^m b^m a^0 = 1 (a^m)^n = a^mn a^m x a^n = a ^ m +n (a/b)^m = a ^
    1. answers icon 1 answer
    2. Susssssssssssss asked by Susssssssssssss
    3. views icon 121 views
  4. How do I use the chain rule to find the derivative ofsquare root(1-x^2) also, are there any general hints or tips for
    1. answers icon 1 answer
    2. Elizabeth asked by Elizabeth
    3. views icon 849 views
  5. what is the derivative of x/tan(x) and find f'(pi/4)f'(x)=(tanx-x*sec(x)^2)/(tanx)^2 That's the quotient rule for derivatives or
    1. answers icon 1 answer
    2. david asked by david
    3. views icon 1,019 views
  6. 8th grade Quotient Rule of Exponents Quick Check ConnexusSimplify this expression using the Quotient Rule of Integer Exponents:
    1. answers icon 24 answers
    2. Anonymus asked by Anonymus
    3. views icon 1,986 views
  7. y= [(x-3)/(x^2+1)]^2find the derivative. I know i would start off with the chain rule. but would i then continue on and use the
    1. answers icon 1 answer
    2. Aaron asked by Aaron
    3. views icon 549 views
  8. Which exponent rule(s) would be used to simplify this expression? 2x5⋅12x−4(1 point) Responses The quotient rule to subtract
    1. answers icon 1 answer
    2. views icon 110 views
  9. Which exponent rule(s) would be used to simplify this expression? 2x^5⋅12x^−4(1 point) Responses The quotient rule to
    1. answers icon 3 answers
    2. not.bta.eli asked by not.bta.eli
    3. views icon 198 views
  10. Match the proper exponent rule (law) below* 5 points (a/b)^m = a^m b^m a^0 = 1 (a^m)^n = a^mn a^m x a^n = a ^ m +n (a/b)^m = a ^
    1. answers icon 1 answer
    2. views icon 107 views