Asked by Sam
Find the derivative of [(2+x)/(x-3)]^(2/5)
I tried the power of a function rule, quotient rule, the chain rule but keep getting stuck.
I tried the power of a function rule, quotient rule, the chain rule but keep getting stuck.
Answers
Answered by
Arora
Yes, you have to use the chain rule here.
Step one:
Take [(2+x)/(x-3)] as y.
d(y^2/5)/dx = (2/5)y^(-3/5), as per the exponent rule for differentiation.
Next, apply the quotient rule on [(2+x)/(x-3)] to get its derivative.
Multiply the answer obtained in both steps for the final answer.
Step one:
Take [(2+x)/(x-3)] as y.
d(y^2/5)/dx = (2/5)y^(-3/5), as per the exponent rule for differentiation.
Next, apply the quotient rule on [(2+x)/(x-3)] to get its derivative.
Multiply the answer obtained in both steps for the final answer.
Answered by
Sam
I got (2/5)[(2+x/x-3)^(-3/5)] (-5/(x-3)^2)
Now I am having troubles simplifying it.
Now I am having troubles simplifying it.
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