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f(x)=5+(6/x)+(7/x^2), find f'(x).

I haven't done fractions without using the quotient rule im not so sure this would work with quotient rule what do i do?

1 answer

rewrite as:
f(x)=5 + 6*x^(-1) + 7*x^(-2)
The derivative of the first term is 0. For the derivative of the terms with x, multiply the exponent times the coeffecient of the term, the subtract 1 from the exponent.
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