The solubility of AgCl is

  1. Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water: solubility =
    1. answers icon 1 answer
    2. JAY_ndabeh asked by JAY_ndabeh
    3. views icon 666 views
  2. Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water:ii) a 0.50 M
    1. answers icon 4 answers
    2. JAY_ndabeh asked by JAY_ndabeh
    3. views icon 1,148 views
  3. Question 2What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for
    1. answers icon 1 answer
    2. Nevaeh asked by Nevaeh
    3. views icon 887 views
  4. Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10(AgCl molecular mass is 143.3g)
    1. answers icon 1 answer
    2. Steve asked by Steve
    3. views icon 4,456 views
  5. Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10(AgCl molecular mass is 143.3g)
    1. answers icon 1 answer
    2. Steve asked by Steve
    3. views icon 828 views
  6. I do not quiet understand what you said. Could you show your work.What is the solubility of AgCl in 10 M NH3? The Kf of
    1. answers icon 1 answer
    2. Nevaeh asked by Nevaeh
    3. views icon 721 views
  7. What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for the balanced
    1. answers icon 1 answer
    2. Nevaeh asked by Nevaeh
    3. views icon 1,086 views
  8. The presence of ammonia in a solution of AgCl will decrease the solubility of AgCl.True Or False
    1. answers icon 2 answers
    2. Katie asked by Katie
    3. views icon 1,145 views
  9. A saturated Agcl was found to have a concentration of 1.30×10^-5 mol.dm3. The solubility product of Agcl therefore is?
    1. answers icon 1 answer
    2. Moses Adeyemi Popoola asked by Moses Adeyemi Popoola
    3. views icon 39 views
  10. Given the following half-reactions, Ag⁺(aq) + e⁻ → Ag(s) E° = +0.799 V, AgCl(s) + e⁻ → Ag(s) + Cl⁻(aq) E° = +0.222
    1. answers icon 0 answers
    2. stefani asked by stefani
    3. views icon 474 views