The average bond enthalpy for

The enthalpy of atomisation is the enthalpy change upon breaking the bonds of 1 mole of a gaseous compound into its atom
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2. asked by Jack
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Bond enthalpy is the energy required to break a mole of a certain type of bond.O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
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2. asked by dereyab
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Bond enthalpy is the energy required to break a mole of a certain type of bond.O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
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2. asked by kira
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Bond enthalpy is the energy required to break a mole of a certain type of bond.O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
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2. asked by Dr BOB plz ANSWER
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HI H- C - O - H I H I thought there is a C-O bond? Is that not used? If it is ignored because we used the full equation average
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2. asked by Why is part 2
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Please explain.The average bond enthalpy for the C-H bond is 412 kJ mol^-1. Which process has an enthalpy change closest to this
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2. asked by Anonymous
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Please explain.The average bond enthalpy for the C-H bond is 412 kJ mol^-1. Which process has an enthalpy change closest to this
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2. asked by Anonymous
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The average bond enthalpy for C__H is 413 kJ/mol. In other words, 413 kJ of energy is required to break a mole of CH into atoms:
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2. asked by sarah
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i tried to do like dis plz chk is it rite or wrong.[2(4(327) + 495 ]- [ 2(4(327) + 523 ] = -28 Bond enthalpy is the energy
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2. asked by Chem Help
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The bond enthalpy of the Br−Cl bond is equal to ƒ¢H�‹ for the reactionBrCl(g) �¨ Br(g) + Cl(g). Use the following data
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2. asked by April
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