Radical ((1-sinx)/(1+sinx))= (1-sinx)/cosx (absolute) Identity

Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
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Radical ((1-sinx)/(1+sinx))= (1-sinx)/cosx (absolute)Identity identity
1. 0 answers
2. asked by Anonymous
3. 485 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
1. 0 answers
2. asked by shan
3. 1,010 views
Verify the Identity:sin(x+π)/cos(x+3π/2) =tan^2x-sec^2x I've done: sinxcosπ+cosxsinπ / cosxcos(3π/2) - sinxsin(3π/2)
1. 2 answers
2. asked by Phil-- HELP NEEDED ASAP
3. 901 views
prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
1. 0 answers
2. asked by JungJung
3. 938 views
Radical ((1-sinx)/(1+sinx))= (1-sinx)/cosx (absolute)Simplify
1. 2 answers
2. asked by Anonymous
3. 455 views
Prove that each of these equations is an identity.A) (1 + sinx + cos x)/(1 + sinx + cosx)=(1 + cosx)/sinx B) (1 + sinx +
1. 2 answers
2. asked by Jonathan
3. 1,411 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,111 views
I need to prove that the following is true. Thanks(cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds
1. 0 answers
2. asked by abdo
3. 1,025 views
Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
1. 0 answers
2. asked by Ashley
3. 1,287 views