Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx]

  1. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
    1. answers icon 3 answers
    2. Anonymous asked by Anonymous
    3. views icon 945 views
  2. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
    1. answers icon 2 answers
    2. Jon asked by Jon
    3. views icon 922 views
  3. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
    1. answers icon 1 answer
    2. Lucy asked by Lucy
    3. views icon 960 views
  4. I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equationProblem 1.
    1. answers icon 2 answers
    2. Alycia asked by Alycia
    3. views icon 721 views
  5. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
    2. Dave asked by Dave
    3. views icon 1,454 views
  6. We are doing trig identities in school. I need help with these five:1.1+sinx/1-sinx=cscx+1/cscx-1 2.tanx+sinx/1+cosx=tanx
    1. answers icon 1 answer
    2. Jay asked by Jay
    3. views icon 958 views
  7. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
    1. answers icon 0 answers
    2. shan asked by shan
    3. views icon 984 views
  8. How do I prove these trig identities?secx-cosx/tanx =sinx And 1+sinx/cosx+ cox/ 1+sinx=2secx
    1. answers icon 1 answer
    2. Jill asked by Jill
    3. views icon 944 views
  9. Prove (1+secx)/(tanx+sinx)=cscx
    1. answers icon 2 answers
    2. Matt asked by Matt
    3. views icon 408 views
  10. Prove (1+secx)/(tanx+sinx)=cscx
    1. answers icon 1 answer
    2. Matt asked by Matt
    3. views icon 507 views