Prove that 2/square root 3cosx-sinx=sec(pi/6-x)

  1. Prove that 2/square root 3cosx-sinx=sec(pi/6-x)
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    2. Nathan asked by Nathan
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  2. hi, i need help solving this trigonometric equation:sinx+3cosx=0 i don't know what to do as i can't just diviide the two to
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    2. elle asked by elle
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  3. Prove: (3cosx + 4sinx)^2 + (4cosx - 3sinx)^2=5 ...this is all under the square root sign.this is what i did please check. i
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    2. just asked by just
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  4. Prove that (2√3+3)sinx+2√3cosx lies between -(2√3+15) and (2√3+15)
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    2. krishan asked by krishan
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  5. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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    2. Anonymous asked by Anonymous
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  6. Prove: (3cosx + 4sinx)^2 + (4cosx - 3sinx)^2=5 ...this is all under the square root sign.I get 9cos^2x + 16sin^2x +16cos^2x +
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    2. linds asked by linds
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  7. 1) evaluate without a calculator: a)sin(3.14/4) b) cos(-3(3.14)/4) c) tan(4(3.14)/3) d) arccos(- square root of three/2) e)
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    2. Emily asked by Emily
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  8. Write the equation of the periodic function based on the graph. (1 point) Responses y = −3cosx y = −3cosx y = 3cosx y =
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  9. If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
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    2. Anonymous asked by Anonymous
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  10. solve equation for exact solution if possible leave answer in degreesinx/2=square root of 2- sinx/2
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    2. mike asked by mike
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