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For the following reaction at 600. K, the equilibrium constant, Kp is 11.5.PCl5(g) PCl3(g) + Cl2(g) Suppose that 3.314 g of PCl5
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2. asked by Anonymous
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At a certain temperature, .5 mol of PCl5 was placed in a .25 L vessel and permitted to react as shownPCl5 (g) --> PCl3 (g)+ Cl2
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2. asked by Alex
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For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.PCl5(g) = PCl3(g) + Cl2(g) Suppose that 2.510 g of
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2. asked by Writeacher
3. 3,017 views
At a certain temperature, 2.00 moles of phosphorus(V) chloride, PCl5, was placed in a 1.0 L vessel and permitted to react as
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2. asked by chem
3. 596 views
PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
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2. asked by Sam
3. 3,416 views
a sample of pcl5 weighing 2.69 placed in 1.0 l flask and completely vaporized at a tem of 250 c the pressur at this tempreture
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2. asked by biran
3. 1,106 views
a sample of pcl5 weighing 2.69 placed in 1.0 l flask and completely vaporized at a tem of 250 c the pressur at this tempreture
1. 1 answer
2. asked by biran
3. 490 views
A 0.229 mol sample of PCL5 is injected into an empty 3.20 L reaction vessel held at 250 degrees celsius. Calculate the
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2. asked by Mer
3. 942 views
PCl5 --> PCl3 + Cl2A 0.318 mol sample of PCl5(g) is injected into an empty 4.15 L reaction vessel held at 250 °C. Calculate the
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2. asked by Jordyn
3. 1,045 views
Phosphorus pentachloride decomposes according to the chemical equationPCl5(g) ⇌ PCl3(g) + Cl2(g) A 0.304 mol sample of PCl5(g)
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2. asked by Dee
3. 605 views