Integrate: dx/sqrt(x^2-9) Answer: ln(x +

Integrate: 1/(x-sqrt(x+2) dxI came up with: (2/3)(2*ln((sqrt(x+2))-2)+ln((sqrt(x+2))-1)) but it keeps coming back the wrong
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Question: ∫(x^2)/sqrt(x^2+1)u=x^2+1 , x^2= u-1, du=2xdx ∫(u-1)/sqrt(u) , expand ∫u/sqrt(u) - 1/sqrt(u) Integrate:
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2. asked by Liam
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Integrate: dx/sqrt(x^2-9)Answer: ln(x + sqrt(x^2 - 9)) + C I'm getting the wrong answer. Where am I going wrong: Substitute: x =
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2. asked by mathstudent
3. 857 views
Please do help solve the followings1) Integrate e^4 dx 2) Integrate dx/sqrt(90^2-4x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4)
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2. asked by Febby-1
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Calc length of arc of y=ln(x) from x=1 to x=2---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x =
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2. asked by mathstudent
3. 666 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
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2. asked by Alexa
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Integrate dx/(sqrt(x^2+16)).I have no idea how to start and which method to use. Thinking some sort of trig substitution? But it
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2. asked by Cindy
3. 544 views
Please can anyone help with the following problems - thanks.1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate
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2. asked by Febby
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When I solve the inquality 2x^2 - 6 < 0,I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
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2. asked by Jen
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So I am supposed to solve this without using a calculator: Sqrt[20]/10 - Sqrt[10]/Sqrt[32] - Sqrt[0.3125] + Sqrt[3 + 1/5]You can
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2. asked by Mr.AMG
3. 830 views