Mr.AMG

So I am supposed to solve this without using a calculator: Sqrt[20]/10 - Sqrt[10]/Sqrt[32] - Sqrt[0.3125] + Sqrt[3 + 1/5] You can put this into WolframAlpha as is to make it prettier. Answer given is 1/2 * SQRT(5) I really don't know where to start here....

35 decimeter string is attached to both ends of a 25 decimeter pole. At what point of the string do you need to pull to make a right triangle?

x^1/3 ÷ (4x)^½ · 16x^-5/4 ÷ 32x I get: x^-5/12 ÷ x = x^(-5/12-12/12) = x^-17/12 but answer given is x^7/12 I'm using a^n / a^m = a^n-m but according to the answer I'm given it seems that I'm supposed to add the 12/12 to -5/12 not subtract them

Thank you Reiny, much appreciated!

Hmm that's what I also thought when I tried to solve this. I get 70L = 600 so L = 600/70 therefore L ~ 8.57 Answer given is 20 dm (or 15 dm) depending on which end of the pole I suppose.

1 Liter = 10 deciliters = 100 centiliters = 1000 milliliters so 1L = 10 dl = 100 cl = 1000 ml Ask yourself, is 1L, which is a measure of volume, likely to be = 1 dm, a measure of length? Hardly. 1 cm cubed, or cm^3, on the other hand is a measure of volum...

We know that a^2 + b^2 = 6^2 since the hypotenuse is 6 ft and this is pythagoras equation (^2 means squared or power of 2). We also know that 6 + a + b = 8 if we name the unknown sides of the triangle a and b. Therefore we can isolate either one, let's ta...

EDIT: a + b = 2 not 8, sorry if I confused you

EDIT: For WolframAlpha cpoy/paste: x^(1/3) / (4x)^(-1/2) * 16x^(-5/4) / 32x