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Mr.AMG
Questions (3)
x^1/3 ÷ (4x)^½ · 16x^-5/4 ÷ 32x
I get: x^-5/12 ÷ x = x^(-5/12-12/12) = x^-17/12 but answer given is x^7/12 I'm using a^n /
1 answer
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35 decimeter string is attached to both ends of a 25 decimeter pole. At what point of the string do you need to pull to make a
2 answers
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So I am supposed to solve this without using a calculator: Sqrt[20]/10 - Sqrt[10]/Sqrt[32] - Sqrt[0.3125] + Sqrt[3 + 1/5]
You can
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Answers (6)
EDIT: For WolframAlpha cpoy/paste: x^(1/3) / (4x)^(-1/2) * 16x^(-5/4) / 32x
EDIT: a + b = 2 not 8, sorry if I confused you
We know that a^2 + b^2 = 6^2 since the hypotenuse is 6 ft and this is pythagoras equation (^2 means squared or power of 2). We also know that 6 + a + b = 8 if we name the unknown sides of the triangle a and b. Therefore we can isolate either one, let's
1 Liter = 10 deciliters = 100 centiliters = 1000 milliliters so 1L = 10 dl = 100 cl = 1000 ml Ask yourself, is 1L, which is a measure of volume, likely to be = 1 dm, a measure of length? Hardly. 1 cm cubed, or cm^3, on the other hand is a measure of
Hmm that's what I also thought when I tried to solve this. I get 70L = 600 so L = 600/70 therefore L ~ 8.57 Answer given is 20 dm (or 15 dm) depending on which end of the pole I suppose.
Thank you Reiny, much appreciated!
