Question

x^1/3 ÷ (4x)^½ · 16x^-5/4 ÷ 32x

I get: x^-5/12 ÷ x = x^(-5/12-12/12) = x^-17/12

but answer given is x^7/12

I'm using a^n / a^m = a^n-m

but according to the answer I'm given it seems that I'm supposed to add the 12/12 to -5/12 not subtract them

Answer 1

EDIT: For WolframAlpha cpoy/paste: x^(1/3) / (4x)^(-1/2) * 16x^(-5/4) / 32x