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In the reaction PCl5(g) --->

PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
1. 2 answers
2. asked by Sam
3. 3,414 views
a 0.76 mol sample of pcl5 is placed in a 500 ml reaction vessel. what is the concentration of pcl5 when the reactionpcl5(g)
1. 1 answer
2. asked by amanda
3. 648 views
For the following reaction at 600. K, the equilibrium constant, Kp is 11.5.PCl5(g) PCl3(g) + Cl2(g) Suppose that 3.314 g of PCl5
1. 1 answer
2. asked by Anonymous
3. 1,192 views
For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.PCl5(g) = PCl3(g) + Cl2(g) Suppose that 2.510 g of
1. 2 answers
2. asked by Writeacher
3. 3,016 views
In the reaction PCl5(g) ---> PCl3(g) + Cl2 (g)0.200 mol of PCl5 is introduced into a 2.00 liter vessel. At equilibrium, the
1. 4 answers
2. asked by josh
3. 667 views
At 250ºC, the equilibrium constant Kp for the reaction PCl5(g) PCl3(g) + Cl2(g)is 1.80. Sufficient PCl5 is put into a reaction
1. 1 answer
2. asked by viamariam
3. 162 views
A 0.229 mol sample of PCL5 is injected into an empty 3.20 L reaction vessel held at 250 degrees celsius. Calculate the
1. 1 answer
2. asked by Mer
3. 940 views
A reaction starts with 1.00 mol each of PCl3 and Cl2 in a 1.00-L flask. When equilibrium is established at 250 degree Celsius in
1. 2 answers
2. asked by Shanice
3. 840 views
PCl5 --> PCl3 + Cl2A 0.318 mol sample of PCl5(g) is injected into an empty 4.15 L reaction vessel held at 250 °C. Calculate the
1. 2 answers
2. asked by Jordyn
3. 1,040 views
Phosphorus pentachloride decomposes according to the chemical equationPCl5(g) ⇌ PCl3(g) + Cl2(g) A 0.304 mol sample of PCl5(g)
1. 0 answers
2. asked by Dee
3. 604 views