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If 2Sinz+2Cosx=1.5.find Sinx+Cosx
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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asked by
shan
1,018 views
If 2Sinz+2Cosx=1.5.find Sinx+Cosx
1 answer
asked by
Bright ulubi
487 views
prove the identity
(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
0 answers
asked by
JungJung
943 views
Having trouble verifying this identity...
cscxtanx + secx= 2cosx This is what I've been trying (1/sinx)(sinx/cosx) + secx = 2cosx
2 answers
asked by
Alex
715 views
Which of the following are trigonometric identities?
(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
1 answer
asked by
Jill
4,837 views
How do you simplify:
(1/(sin^2x-cos^2x))-(2/cosx-sinx)? I tried factoring and creating a LCD of (sinx+cosx)(sinx cosx)
2 answers
asked by
Shannon
618 views
solve each equation for 0=/<x=/<2pi
sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
7 answers
asked by
sh
999 views
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,119 views
by equating the coefficients of sin x and cos x , or otherwise, find constants A and B satisfying the identity.
A(2sinx + cosx) +
1 answer
asked by
Candice
676 views
If y=3/(sinx+cosx) , find dy/dx
A. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
1 answer
asked by
Anonymous
701 views