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How do you solve sin2θ−cosθ=0

If θ represents an angle such that sin2θ = tanθ - cos2θ, then sin θ - cosθ =A. -√2 B. 0 C. 1 D. 2√2 What equation can
1. 3 answers
2. asked by Peter
3. 1,819 views
How do you solve sin2θ−cosθ=0 between -pi/2 less than or equal to θ less than or equal to 3pi/2?
1. 2 answers
2. asked by Anonymous
3. 492 views
can someone help me prove the identities on this:1- 1/2 sin2θ = sin^3θ + cos^3θ / sinθ + cosθ
1. 1 answer
2. asked by Albert
3. 515 views
Solve the following equations giving any roots in terms of pi in the .......?interval -2pi ≤ 0 ≤ 2pi. a) 2cos²Θ + sin²Θ
1. 2 answers
2. asked by raj
3. 570 views
if cosθ=2/3 and tanθ<0 find the exact valuesin(θ-5π/3) sin2θ cos2θ cos(θ/2) can some1 please help me?
1. 0 answers
2. asked by Yulieth
3. 490 views
if cosθ=2/3 and tanθ<0 find the exact valuesin(θ-5π/3) sin2θ cos2θ cos(θ/2) can some1 please help me?
1. 1 answer
2. asked by Yulieth
3. 939 views
I really don't understand how to write the expression as one invloving only sinϴ and cosϴsin2ϴ+cos3ϴ
1. 1 answer
2. asked by wade
3. 435 views
Ana was asked to use triangles formed by angles on the unit circle to prove the Pythagorean Identity sin2θ+cos2θ=1, where
1. 1 answer
2. 217 views
How do I prove that secθ - tanθsinθ = cosθSo far I have LS 1/cosθ - sinθ/cosθ (sinθ) =1/cosθ -sin^2/cosθ
1. 1 answer
2. asked by Trisha
3. 2,042 views
Ana was asked to use triangles formed by angles on the unit circle to prove the Pythagorean Identity sin2θ+cos2θ=1 , where
1. 1 answer
2. 27 views