How do you solve sin2θ−cosθ=0

  1. If θ represents an angle such that sin2θ = tanθ - cos2θ, then sin θ - cosθ =A. -√2 B. 0 C. 1 D. 2√2 What equation can
    1. answers icon 3 answers
    2. Peter asked by Peter
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  2. How do you solve sin2θ−cosθ=0 between -pi/2 less than or equal to θ less than or equal to 3pi/2?
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    2. Anonymous asked by Anonymous
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  3. can someone help me prove the identities on this:1- 1/2 sin2θ = sin^3θ + cos^3θ / sinθ + cosθ
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    2. Albert asked by Albert
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  4. Solve the following equations giving any roots in terms of pi in the .......?interval -2pi ≤ 0 ≤ 2pi. a) 2cos²Θ + sin²Θ
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    2. raj asked by raj
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  5. if cosθ=2/3 and tanθ<0 find the exact valuesin(θ-5π/3) sin2θ cos2θ cos(θ/2) can some1 please help me?
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    2. Yulieth asked by Yulieth
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  6. if cosθ=2/3 and tanθ<0 find the exact valuesin(θ-5π/3) sin2θ cos2θ cos(θ/2) can some1 please help me?
    1. answers icon 1 answer
    2. Yulieth asked by Yulieth
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  7. I really don't understand how to write the expression as one invloving only sinϴ and cosϴsin2ϴ+cos3ϴ
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    2. wade asked by wade
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  8. Ana was asked to use triangles formed by angles on the unit circle to prove the Pythagorean Identity sin2θ+cos2θ=1, where
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  9. How do I prove that secθ - tanθsinθ = cosθSo far I have LS 1/cosθ - sinθ/cosθ (sinθ) =1/cosθ -sin^2/cosθ
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    2. Trisha asked by Trisha
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  10. Ana was asked to use triangles formed by angles on the unit circle to prove the Pythagorean Identity sin2θ+cos2θ=1 , where
    1. answers icon 1 answer
    2. views icon 19 views