Asked by Trisha
How do I prove that secθ - tanθsinθ = cosθ
So far I have
LS
1/cosθ - sinθ/cosθ (sinθ)
=1/cosθ -sin^2/cosθ
So far I have
LS
1/cosθ - sinθ/cosθ (sinθ)
=1/cosθ -sin^2/cosθ
Answers
Answered by
Reiny
LS = secθ - tanθsinθ
= 1/cosØ - (sinØ/cosØ)sinØ
= 1/cosØ - sin^2Ø/cosØ
= (1 - sin^2 Ø)/cosØ ---> you had it up to there
= cos^2 Ø/cosØ ---> since sin^2 Ø + cos^2 Ø = 1
= cosØ
= RS
= 1/cosØ - (sinØ/cosØ)sinØ
= 1/cosØ - sin^2Ø/cosØ
= (1 - sin^2 Ø)/cosØ ---> you had it up to there
= cos^2 Ø/cosØ ---> since sin^2 Ø + cos^2 Ø = 1
= cosØ
= RS
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