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Equivalence point Volume of 14mL
Equivalence point Volume of 14mL and a conductivity of 44.
Sulfuric Acid=0.020M and 13mL Barium Hydroxide=100mL -Determining the
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Anonymous
471 views
How do you figure equivalence volume? Do I add up all of the additions during my lab up to the point I am measuring (color
2 answers
asked by
Thomas
529 views
In this case, the inflection point, and
equivalence, occurs after 23.25mL of 0.40 M NaOH has been delivered. Moles of base at the
1 answer
asked by
John
847 views
The number of moles NaOH needed to reach the equivalence point is
mol, which means we must add liters of NaOH. The total volume
1 answer
asked by
Elizabeth
578 views
A 60.00 ml aliquot of a week acid HA is titrated with
0.1000M NaOH. The equivalence volume is 30.00 ml. pH at the equivalence
1 answer
asked by
ngo
443 views
Explain why the volume of 0.100 M NaOH required to reach the equivalence point in the titration of 25.00 mL of 0.100 M HA is the
1 answer
asked by
kobe
3,210 views
A 30 mL sample of .165 M propanoic acid is titrated with .300M KOH. Calculate the pH at each volume of added base: 0 mL, 5 mL,
2 answers
asked by
Anonymous
1,882 views
1) Using the 1st equivalence point from part a calculate the molarity of the phosphoric acid. Molarity of NaOH = .1523 M
Volume
4 answers
asked by
Maura
3,294 views
A 0.2512 stock sample of HCl is tirade to equivalence . If 16.77ml of 0.1410 M NaOH is required to reach the equivalence point,
3 answers
asked by
Nicole
786 views
A 40.00 mL sample of 0.1 M NH3 is titrated with 0.150 M HCl solution. Kb = 1.8 * 10^-5
What volume of base is required to reach
5 answers
asked by
Emily
1,017 views