Asked by Nicole
A 0.2512 stock sample of HCl is tirade to equivalence . If 16.77ml of 0.1410 M NaOH is required to reach the equivalence point, what volume of stock HCl was used for the tritation?
Answers
Answered by
DrBob222
Is that 0.2512 M stock? I will assume it is.
mols NaOH = M x L = ?
mols HCl = mols NaOH (since 1 mol HCl = 1 mol NaOH in the balanced equation).
M HCL stock = mols/L.
You know M and you know mols, solve for L and change to mL if desired.
mols NaOH = M x L = ?
mols HCl = mols NaOH (since 1 mol HCl = 1 mol NaOH in the balanced equation).
M HCL stock = mols/L.
You know M and you know mols, solve for L and change to mL if desired.
Answered by
Nicole
yes 0.2512 M stock so,
0.1410m x 0.01677L= 2.36457^-03 mole used.
mols HCL = mols NaOH 0.2512M=2.36457^3
0.1410m x 0.01677L= 2.36457^-03 mole used.
mols HCL = mols NaOH 0.2512M=2.36457^3
Answered by
Nicole
What am I missing ?
Should there be another step?
Should there be another step?
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