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Differentiate Y = 1/SinX^2
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
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Anonymous
953 views
Differentiate
(1- sinx) / (1 +sinx) How would I do this? The answer is (-2cosx)/ (1 + sinx)^2 Thanks in advance :)!!
1 answer
asked by
Allessandra
521 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm
(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
3 answers
asked by
Anonymous
789 views
I think I have the correct answers for the following problems. For anyone who has the time I would appreciate it if you could
0 answers
asked by
Linda
703 views
Simplify sin x cos^2x-sinx
Here's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1 answer
asked by
Tara
1,063 views
Prove that xcosx< sinx for 0<x<(5π/4)
-differentiate the function f(x)=sinx-xcosx
1 answer
asked by
MTH3312
589 views
Differentiate: a) y= x^2/ sinx
b) y= In(2x^3+x)
3 answers
asked by
Anonymous
479 views
Differentiate
Y = 1/SinX^2
1 answer
asked by
Francis
636 views
Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
1 answer
asked by
Maggie
864 views
Differentiate.
f(x)=5sqrt(x)sinx
1 answer
asked by
TayB
584 views