Asked by Anonymous
Differentiate: a) y= x^2/ sinx
b) y= In(2x^3+x)
b) y= In(2x^3+x)
Answers
Answered by
bobpursley
I will be happy to critique your work here. These are standard formulas.
Answered by
Anonymous
a) =2x^1(x^2)/xcos(sinx)?
Answered by
Reiny
I can't see you you came up with that very strange looking answer.
As bobpursley pointed out, this is a direct application of the quotient rule
I got
dy/dx = (2x sinx - x^2 cosx)/(sin^2 x)
simplification would leave to several final versions of an answer, certainly not yours.
the 2nd is even easier.
dy/dx = (6x^2+1)/(2x^3 + x)
As bobpursley pointed out, this is a direct application of the quotient rule
I got
dy/dx = (2x sinx - x^2 cosx)/(sin^2 x)
simplification would leave to several final versions of an answer, certainly not yours.
the 2nd is even easier.
dy/dx = (6x^2+1)/(2x^3 + x)
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