Asked by Anonymous
1/sinx - sinx = cosx/tanx
Answers
Answered by
Steve
if you set the left side over a common denominator of sinx, you have
1/sinx - sin^2x/sinx
(1-sin^2 x)/sinx
If that does not get you started, I don't know what will...
1/sinx - sin^2x/sinx
(1-sin^2 x)/sinx
If that does not get you started, I don't know what will...
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