Ask a New Question

Question

solve sinx/2,cosx/2 & tanx/2 of the following:-
(a)sinx=1/4 & x lies in second quadrant.
10 years ago

Answers

Steve
draw your triangle
the other side is √15

since we are in QII and sin is positive,

x = -√15
y = 1
r = 4
so, cosx = -√15/4

Now use those values to plug into your half-angle formulas.
10 years ago
Musharraf
Detail
7 years ago

Related Questions

tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx... cosx/1-tanx + sinx/1-cotx = sinx =cosx Show that tanx= (sinx/ cosx) can be written as: tan(x-y) = (tanx - tany) / (1+ tanxtany) solve (sq.rt 2) (tanx)(cosx) = tanx find cosx and sinx if tanx = 4 How do i solve sinx/cosx(sinx+cosx/sinx×cosx)=secx? I know it's 1/cosx because it equals secx but... 1/sinx - sinx = cosx/tanx Solve tanx+cosx/1+sinx=secx In two different ways Solve for: 1+cosx/sinx + sinx/1+cosx = 1 My teacher said no solution, but I don't know how he go... (secx-cosx) / (tanx-sinx) = cosecx+cotx Spent hours to solve this question but failed. Please hel...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use