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Consider the following equilibrium: N2O4
A 1.00 mol sample of N2O4 (g) is placed in a 10.0 L vessel and allowed to reach equilibrium accourding to the equation
N2O4(g)
2 answers
asked by
kevin
3,661 views
The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the
3 answers
asked by
Beth
1,563 views
The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the
2 answers
asked by
Audrey
1,107 views
Dinitrogen tetroxide decomposes to nitrogen dioxide:
N2O4 (g) ---> 2NO2 (g) Delta H rxn: 55.3 kJ At 298 K a reaction vessel
1 answer
asked by
Tyler
2,260 views
Dinitrogen tetroxide decomposes to nitrogen dioxide:
N2O4(g)→2NO2(g)ΔHorxn=55.3kJ At 298 K, a reaction vessel initially
1 answer
asked by
Justiss
4,786 views
A chemist studying the equilibrium N2O4(g)<----->2NO2(g) controls the temperature so that keq ( equilibrium constant)= 0.028. At
1 answer
asked by
Anonymous
1,030 views
When heated, N2O4 dissociates as follows: N2O4 =2NO2
A flask initially contians .560 M N2O4. at this temperature, Kc is 4.00.
2 answers
asked by
Rob
1,044 views
At 55C, the K for the reaction: 2NO2(g) <--> N2O4 is 1.15
a) write the equilibrium expression b) calculate the concentration of
5 answers
asked by
Anonymous
1,401 views
Dinitrogentetraoxide partially decomposes according to the following equilibrium:
N2O4 (g) -> 2NO2 (g) <- A 1.00-L flask is
6 answers
asked by
Jane
4,191 views
I need help. I have no clue how to find this.
A flask is charged with 1.680 atm of N2O4(g) and 1.220 atm of NO2(g) at 25 degrees
1 answer
asked by
Alexus
581 views