The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the reaction mixture with no change in volume, what will be the new equilibrium concentration of N2O4?
N2O4(g) 2 NO2(g)
2 answers
UGH! I've been working on this problem for about an hour now for my test tomorrow at WMU. No luck. =( My guess? Impossible. =P
The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the reaction mixture with no change in volume, what will be the new equilibrium concentration of N2O4?
N2O4(g) 2 NO2(g)
N2O4(g) 2 NO2(g)