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A mixture contains n2o4 and
92.01 grams of N2O4 (g) is placed in a container and allowed to dissociate.
N2O4 (g) --> 2NO2 (g) The mixture of N2O4 and NO2
2 answers
asked by
Neha
998 views
Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At
2 answers
asked by
Kailee
2,934 views
At 25∘C, 0.11 mol of N2O4 reacts to form 0.10 mol of N2O4 and 0.02 mol of NO2. At 90∘C, 0.11 mol of N2O4 forms 0.050 mol of
2 answers
asked by
Person
561 views
A reaction mixture of N2O4 and NO2 absorbs the heat given off in the combustion of 6.35 L CH4 measured at 24.7 C and 812 Torr.
1 answer
asked by
maddie
814 views
The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the
3 answers
asked by
Beth
1,600 views
The following system is at equilibrium with [N2O4] = 0.55 M and [NO2] = 0.25 M. If an additional 0.10 M NO2 is added to the
2 answers
asked by
Audrey
1,125 views
1-Dinitrogen tetroxide (N2O4) dissociates according to the equation:
N2O4 ⇌ 2NO2 An equilibrium reaction mixture at 25 ºC was
3 answers
asked by
John
1,868 views
Dinitrogen tetroxide decomposes to nitrogen dioxide:
N2O4 (g) ---> 2NO2 (g) Delta H rxn: 55.3 kJ At 298 K a reaction vessel
1 answer
asked by
Tyler
2,295 views
the total pressure of n2o4 and no2 IS 1.38 atm. if kp is 6.75(25 C) calculate partial pressure of NO2 in the mixture. 2NO2<--->
5 answers
asked by
anon
1,207 views
Dinitrogen tetroxide decomposes to nitrogen dioxide:
N2O4(g)→2NO2(g)ΔHorxn=55.3kJ At 298 K, a reaction vessel initially
1 answer
asked by
Justiss
4,822 views