40.0 grams of Al2S3 are

  1. If 48.1 g of solid Al2S3 and 6.68 mL of liquid H2O are reacted stoichiometrically according to the balanced equation, how many
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    2. Judy asked by Judy
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  2. If 48.1 g of solid Al2S3 and 6.68 mL of liquid H2O are reacted stoichiometrically according to the balanced equation, how many
    1. answers icon 2 answers
    2. Judy asked by Judy
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  3. Al+S=Al2S3Balanced equ= 2Al+3S=Al2S3 10 grams of Al were mixed with 15 gram of S Find: limiting reagent al or s? How much Al2S3
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    2. malina asked by malina
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  4. if the yieeld for the following reaction is 85% how many grams of Al2S3 should be used to produce 165 g of Al(OH)3?Al2S3+6H2O-->
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    2. annabel asked by annabel
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  5. Al_S=Al2S310 grams of Al were mixed with 15 gram of S Find: limiting reagent al or s? How much Al2S3 were formed in reaction?
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    2. mal asked by mal
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  6. Column A1. Al2S3 : Al2S3 2. FeCl3 : FeCl3 3. CuCO3 : CuCO3 Column B a.59.05 grams/mol b.91.56 grams/mol c.91.30 grams/mol
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  7. Just checking an answer...I was given Aluminum + Sulfur yields.. & I was to finish & balance & answer the questions. 2Al + 3S =>
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    2. anna asked by anna
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  8. Based on the balanced equationAl2S3 + 6H2O → 2Al(OH)3 + 3H2S calculate the number of excess reagent units remaining when 4
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    2. SIMON asked by SIMON
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  9. Determine the theoretical yield of H2S (in moles) if 30 mol Al2S3 and 30 mol H2O are reacted according to the following balanced
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  10. Is this equation correctly balanced? If not why.Al2S3+H2O----> Al2S3+3H2O---->Al2(SO)3+3H2
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    2. What? asked by What?
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