Asked by annabel

if the yieeld for the following reaction is 85% how many grams of Al2S3 should be used to produce 165 g of Al(OH)3?


Al2S3+6H2O-->2Al(OH)3+3H2S
Answered by DrBob222
165 g Al(OH)3 = how many mols.
mols = grams/molar mass.

If the yield is only 85%, then you must produce more than that. How much more?
yield = 0.85 = (actual value/theoretical value) = (?mols/x) and solve for x.

Convert mols (x) Al(OH)3 to mols Al2S3. Then g Al2S3 = mols x molar mass.
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