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2tan^2x-tanx-1=0 0

2tan^2x-tanx-1=00<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
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2tan^2x-tanx-1=00<x<2pi
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Verify the following:1. cos x/(1-sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x -
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2tan^-1(tanx/2×tan(π/4-y/2))=tan^-1(sinx×siny/cosx+cosy)
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Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all.a.
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For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
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Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
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Complete the following identity secx-1/secx=? I have four multiple choice options and can't seem to work my way to either one.
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