2n2o5(g)→4no2(g)+o2(g) when 40g of n2o5

  1. CHEMICAL KINETICSThe rate of reaction 2N₂O5->4NO₂+O₂ can be written in three ways -d[N₂O5]/dt= k[N₂O5] d[NO₂]/dt=
    1. answers icon 0 answers
    2. tanya asked by tanya
    3. views icon 677 views
  2. CHEMICAL KINETICSThe rate of reaction 2N₂O5->4NO₂+O₂ can be written in three ways -d[N₂O5]/dt= k[N₂O5] d[NO₂]/dt=
    1. answers icon 1 answer
    2. sam asked by sam
    3. views icon 733 views
  3. 2N2O5->4NO2+O2,d[N2O5]/dt=k1[N2O5],d[NO2]/dt=k2[N2O5]andd[O2]/dt=k3[N2O5],the relation betweenk1,k2and k3 is what?
    1. answers icon 0 answers
    2. devi asked by devi
    3. views icon 1,347 views
  4. For the decompostion of gaseous dinitrogen pentaoxide, 2N2O5(g)--->4NO2(g) +O2(g) . The rate constant is k=2.8 x 10^-3 at 60
    1. answers icon 1 answer
    2. sabrina asked by sabrina
    3. views icon 1,487 views
  5. The first-order rate constant for the decomposition of N2O5, 2N2O5(g) --> 4NO2(g) + O2(g), at 70 degrees C is 6.82 x 10^-3 s^-1.
    1. answers icon 3 answers
    2. M asked by M
    3. views icon 1,461 views
  6. The mechanism for the reaction described by2N2O5(g) ---> 4NO2(g) + O2(g) is suggested to be (1) N2O5(g) (k1)--->(K-1) NO2(g) +
    1. answers icon 2 answers
    2. Mia asked by Mia
    3. views icon 5,682 views
  7. hiI need help with this question please. 1. consider the decomposition of N2O5 in carbon tetrachloride(ccl4) at 45c
    1. answers icon 1 answer
    2. hrithik asked by hrithik
    3. views icon 1,116 views
  8. The following data are obtained for the decomposition of N2O5 at a certain temperature:2N2O5(g)↔4NO2(g) + O2(g) Time(s) 0 200
    1. answers icon 3 answers
    2. cara asked by cara
    3. views icon 1,855 views
  9. 2n2o5(g)→4no2(g)+o2(g) when 40g of n2o5 decompose 4.5g of o2 is formed what is the percent yield
    1. answers icon 5 answers
    2. Anonymous asked by Anonymous
    3. views icon 2,135 views
  10. 2N2o5->4no2+of2,when 40g of N2o5 and 4.5 of oxygen. Calculate theoretical yield.
    1. answers icon 1 answer
    2. Dag asked by Dag
    3. views icon 143 views