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25ml of 0.01M KIO3 solution
25ml of 0.01M KIO3 solution were put to react with an excess of KI. 32.04ml of the sodium thiosulfate solution were needed to
1 answer
asked by
vicky
771 views
Weight out accurately 0.14-0.15g of pure dry KIO3 , dissolve it in 25ml of distilled water. Add 2 g of potassium iodate and 2ml
1 answer
asked by
Arshana
232 views
1a) Calculate the molar concentration of the KIO3 solution provided.
KIO3 2.15g/L we used 10 mL in the experiment.
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asked by
Sherry
1,608 views
how many grams of KIO3 are needed to make 50.0 mL of a 1.2 M KIO3 solution
1 answer
asked by
Anonymous
951 views
Hi
I just need help with question (ii) and (iii), i know how to work out (i) A solution is prepared by dissolving 0.2222
1 answer
asked by
Jenny
639 views
The original 10 ml (KIO3) solution is 0.020M is mixed with 10 mL of 0.0020M NaHSO3 which give a total volume of 20 mL. Calculate
1 answer
asked by
Raj
960 views
1) A 25mL sample of the .265M HCI solution from the previous question is
titrated with a solution of NaOH. 28.25mL of the NaOH
5 answers
asked by
Jessica
1,002 views
What mass of KIO3 is needed to convert the copper in 0.200g of CuSO4.H2O to Cu(IO3)2?
my answer is: 0.828g Cu(IO3)2 x (2*214.003
1 answer
asked by
xavier
3,622 views
A solution is prepared by dissolving 0.2222 (¡¾0.0002) g of KIO3 in 50.00 (¡¾0.05) mL.
(i) Calculate the molar mass of KIO3
0 answers
asked by
Matt
970 views
A solution is prepared by dissolving 0.2222 (¡¾0.0002) g of KIO3 in 50.00 (¡¾0.05) mL.
(i) Calculate the molar mass of KIO3
0 answers
asked by
Hobson
638 views