What mass of KIO3 is needed to convert the copper in 0.200g of CuSO4.H2O to Cu(IO3)2?

Question

my answer is:

0.828g Cu(IO3)2 x (2*214.003 MolarM KIO3/ 413.36 MolarM Cu(IO3) = 0.857g KIO3

could you please check if i got it right

Answer 1

It's tough to figure out what you did? You haven't used the 0.200 g CuSO4.5H2O at all, or at least it isn't obvious that you have unless the 0.828 is the converted mass of CuSO4.5H2O