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1. 2log8^x=log8(4x+12) both log bases

  1. How do I start to solve -2log8(x+1) = -8?I think -2log8(x+1) is log8^(x+1)to the 2nd but then what do I do because then I think
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    2. Anna asked by Anna
    3. views icon 598 views
  2. 1. 2log8^x=log8(4x+12)both log bases are 8. I have no clue what to do. 2. 1/2ln (x) -3 ln y - ln (z-2) so far for this second
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    2. Billy asked by Billy
    3. views icon 591 views
  3. Hi Reiny, I posted this problem earlier and you responded but I don't get the reasoning-The problem was -2log8(x+1) = -8 you
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    2. Anna asked by Anna
    3. views icon 619 views
  4. Simply using laws of logarithms2log8^2+2log8^3 I tried this question I failed
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    2. john asked by john
    3. views icon 495 views
  5. Which of the following expressions correctly expands log16 to its simplest form?(1 point)Responses log8⋅log2 logarithm 8 times
    1. answers icon 1 answer
    2. views icon 138 views
  6. Expand the expression log(8x5) using the properties of logarithms.(1 point) Responses log8+logx log8+logx log8+logx−log5
    1. answers icon 1 answer
    2. pakyo asked by pakyo
    3. views icon 46 views
  7. Drop the logs solve for xlog8 x + log8 (x + 6) = log8 (5x + 12)
    1. answers icon 1 answer
    2. views icon 59 views
  8. Solve for the value of x: log5(x-2)+log8(x-4)=Log6(x-1)..For your information that 5,8 and 6 are bases not just multipliers.
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    2. Seth asked by Seth
    3. views icon 534 views
  9. Which of the following correctly uses the Product Rule of Logarithms to find an equivalent expression to log24 ?(1 point)
    1. answers icon 1 answer
    2. views icon 163 views
  10. Expand the logarithmic expression.log8 a/2 My answer is log8a-log8 2
    1. answers icon 28 answers
    2. Steve asked by Steve
    3. views icon 18,833 views