(secx-cosx) / (tanx-sinx) = cosecx+cotx

My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
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2. asked by Jon
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(secx-cosx) / (tanx-sinx) = cosecx+cotxSpent hours to solve this question but failed. Please help. Thank you
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2. asked by Aina
3. 650 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
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1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
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2. asked by olivia
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I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equationProblem 1.
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2. asked by Alycia
3. 714 views
1. (sinx/cscx)+(cosx/secx)=12. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4.
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2. asked by Tom
3. 764 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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2. asked by Anonymous
3. 1,073 views
Write in terms of cos and sin function.cotx*secx Show work. I know cotx = cosx/sinx and secx = 1/cosx, would that just be the
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2. asked by Need this asap please
3. 617 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 979 views
5. verify each of the following identitiesa) (sinx -cosx)(cscx+secx) =tanx-cotx b) sec2x- csc2x= tan2x- cot2x
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2. asked by Nati
3. 25 views