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(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x

  1. (sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x
    1. answers icon 1 answer
    2. mike asked by mike
    3. views icon 570 views
  2. write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
    1. answers icon 0 answers
    2. Kalen asked by Kalen
    3. views icon 574 views
  3. write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
    1. answers icon 0 answers
    2. jake asked by jake
    3. views icon 949 views
  4. write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
    1. answers icon 1 answer
    2. kate asked by kate
    3. views icon 527 views
  5. if sin2x=3sin2y,prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and
    1. answers icon 7 answers
    2. aayush asked by aayush
    3. views icon 3,418 views
  6. d/dx(e^sinx2x)=a)-cos2xe^sinx2x b)cosxe^sin2x c)2e^sin2x d)2cos2xe^sin2x e)-2cos2xe^sin2x
    1. answers icon 1 answer
    2. victoria asked by victoria
    3. views icon 927 views
  7. Verify the trigonometric identity:[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.
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    2. Matt asked by Matt
    3. views icon 676 views
  8. Verify the trigonometric identity:[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.
    1. answers icon 2 answers
    2. Matt asked by Matt
    3. views icon 1,336 views
  9. since sin2x+√3cos2x=2sin(2x+60) find the general solution for the equation sin2x+√3cosx=0thank you
    1. answers icon 1 answer
    2. phillip asked by phillip
    3. views icon 629 views
  10. Can someone help me find ALL solutions in the interval [0,2π) for the given equations. Please show work.1) sin2x = sin2x 2)
    1. answers icon 2 answers
    2. Jane asked by Jane
    3. views icon 705 views