aayush

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y)

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)

The parelel side of a trapezium is 65m 40m its nonparallel sides are 39 m56m find the area

A hostel provision of food for 28 days for 40 girls. How many days the food item will last if 16 new girls are admitted in the hostel

Integration of 1/x with respect to x is natural logarithm of x

find the force exerted by these two equal charges by using f=(1/4*pi*epsilon)*(q1*q2)/r^2 if f1 is the force exerted by one charge q1 and f2 be the force exerted by another charge q2 which are equal in their magnitude(as you've mentioned) then f1=f2=f. i....

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)

metals are the good conductor of heat. hence, metals can gain heat by contact. so, the cup with the metal spoon will cool faster.

cause the air comes in thermal equlibrium with your body... and it depends upon the heat that your body looses...i guess so.

q=(n*e).....(i) where, q= charge, n=number, e= charge of an electron n=q/e....(i) (from equation i) given,q= +2.8mc= +2.8*10^-6 c we know, charge of an electron(e)=1.6*10^-19 c hence n= (2.8*10^-6)/(1.6*10^-19) = 1.75*10^13 so, 1.75*10^13number of charges...

q=(n*e).....(i) where, q= charge, n=number, e= charge of an electron n=q/e....(i) (from equation i) given,q= +2.8mc= +2.8*10^-6 c we know, charge of an electron(e)=1.6*10^-19 c hence n= (2.8*10^-6)/(1.6*10^-19) = 1.75*10^13 so, 1.75*10^13number of charges...

please help me

right

4mm