Asked by mike
(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x
Answers
Answered by
Steve
I don't think the identity holds. Plug in x = pi/6.
Graph (sec6x+sin2x)/(sin6x-sin2x)-tan4xcot2x
and you don't get zero.
Graph (sec6x+sin2x)/(sin6x-sin2x)-tan4xcot2x
and you don't get zero.
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