Asked by Hejumacla
solve :3 sin^2 x-cos^2 x=sin2x
Answers
Answered by
Steve
since cos2x = cos^2x - sin^2x, you have
1 - 2cos2x = sin2x
1 - 4cos2x + 4cos^2 2x = sin^2 2x
5cos^2 2x - 4cos2x = 0
cos(2x)(5cos(2x)-4) = 0
cos 2x = 0
cos 2x = 4/5
1 - 2cos2x = sin2x
1 - 4cos2x + 4cos^2 2x = sin^2 2x
5cos^2 2x - 4cos2x = 0
cos(2x)(5cos(2x)-4) = 0
cos 2x = 0
cos 2x = 4/5
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