Asked by Leslie
Solve lim sin2x using any method.
×>0 -----
5x
I am unaware of what my first step is supposed to be, I know that if I plug in 0 to x, I will receive an answer of 0/0, and that makes my answer indeterminate. So what happens after that?
×>0 -----
5x
I am unaware of what my first step is supposed to be, I know that if I plug in 0 to x, I will receive an answer of 0/0, and that makes my answer indeterminate. So what happens after that?
Answers
Answered by
Steve
You know that
lim sinu/u = 1, so
sin2x/5x = sin2x/2x * 2/5
lim sinu/u = 1, so
sin2x/5x = sin2x/2x * 2/5
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