Asked by Cassie
Solve using two different methods. Explain which method you found to be most efficient.
A.
3x - 9y = 3
6x - 3y = -24
B.
7x - 3y = 20
5x + 3y = 16
C.
y = 1/2x - 6
2x + 6y = 19
I am just stuck and don't know how to do these last few problems on my assignment. If someone would please help it would be very much appreciated. Thank You.
A.
3x - 9y = 3
6x - 3y = -24
B.
7x - 3y = 20
5x + 3y = 16
C.
y = 1/2x - 6
2x + 6y = 19
I am just stuck and don't know how to do these last few problems on my assignment. If someone would please help it would be very much appreciated. Thank You.
Answers
Answered by
Kuai
A. Elimination method
-6x +18y = -6
6x -3y = -24
15y = -30
y = -2
x = -5
(-5,-2)
B. Elimination method
7x -3y = 20
5x +3y = 16
12x = 36
x = 3
y = 1/3
(3, 1/3)
C . Substitution method
y =x/2 -6
2x + 6y = 19
2x + 6 (x/2 -6) = 19
2x + 3x -36 = 19
5x -36 = 19
5x = 55
x = 11
y = -1/2
(11, -1/2)
-6x +18y = -6
6x -3y = -24
15y = -30
y = -2
x = -5
(-5,-2)
B. Elimination method
7x -3y = 20
5x +3y = 16
12x = 36
x = 3
y = 1/3
(3, 1/3)
C . Substitution method
y =x/2 -6
2x + 6y = 19
2x + 6 (x/2 -6) = 19
2x + 3x -36 = 19
5x -36 = 19
5x = 55
x = 11
y = -1/2
(11, -1/2)
Answered by
Cassie
Thank you so much. But I need 2 ways to solve each one, can you show me another method for each.
Answered by
Damon
I will give you the substitution method for b. Then you do a and c
B. substitution method
7x -3y = 20
7 x = 3 y + 20
x = (3/7)y + 20/7
then
5x +3y = 16
5[ (3/7)y + 20/7 ] + 3 y = 16
(15/7)y + 100/7 + 21/7 y = 112/7
36 y = 12
y = 1/3
go back and get x
B. substitution method
7x -3y = 20
7 x = 3 y + 20
x = (3/7)y + 20/7
then
5x +3y = 16
5[ (3/7)y + 20/7 ] + 3 y = 16
(15/7)y + 100/7 + 21/7 y = 112/7
36 y = 12
y = 1/3
go back and get x
Answered by
Cassie
Ok. Thank you.
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