Asked by Lauren
solve:
Sin2x=Sinx
Sin2x=Sinx
Answers
Answered by
Reiny
sin 2x = sinx
2sinxcosx-sinx = 0
sinx(2cosx - 1) = 0
sinx = 0 or cosx = 1/2
in degrees,
x = 0, 180, 360 or x = 60 , 300 , for 0 ≤ x ≤ 360°
in radians,
x = 0, π, 2π or x = π/3, 5π/3
2sinxcosx-sinx = 0
sinx(2cosx - 1) = 0
sinx = 0 or cosx = 1/2
in degrees,
x = 0, 180, 360 or x = 60 , 300 , for 0 ≤ x ≤ 360°
in radians,
x = 0, π, 2π or x = π/3, 5π/3
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