Question
Prove:
sin2x*sinx/2cosx + cos^2 0 = 1
sin2x*sinx/2cosx + cos^2 0 = 1
Answers
Reiny
I corrected your typo
sin(2x)*sinx/2cosx + cos^2 x = 1
LS = 2sinxcosx(sinx)/(2cosx) + cos^2x
= sinx(sinx) + cos^2 x
= sin^2 x + cos^2 x
= 1
= RS
sin(2x)*sinx/2cosx + cos^2 x = 1
LS = 2sinxcosx(sinx)/(2cosx) + cos^2x
= sinx(sinx) + cos^2 x
= sin^2 x + cos^2 x
= 1
= RS
Anonymous
Thank you! :)