Asked by Amanda
1+sin2x/sin2x=1+1/2(secx)(cscx)
Answers
Answered by
Steve
1 + sin2x = 1 + 2sinx cosx
divide by 2sinx cosx to get
1/(2sinx cosx) + 1
= 1/2 cscx secx + 1
divide by 2sinx cosx to get
1/(2sinx cosx) + 1
= 1/2 cscx secx + 1
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